5n^2+6n-94=10

Solution for 5n^2+6n-94=10 equation:

5n^2+6n-94=10

We move all terms to the left:

5n^2+6n-94-(10)=0

We add all the numbers together, and all the variables

5n^2+6n-104=0

a = 5; b = 6; c = -104;
Δ = b2-4ac
Δ = 62-4·5·(-104)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-46}{2*5}=\frac{-52}{10}
=-5+1/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+46}{2*5}=\frac{40}{10}
=4
$